Bound states for a Spherically Symmetric Schrodinger equation

stunner5000pt
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Homework Statement


A particle of mass m moves in three dimensions in a potential energy field
V(r) = -V0 r< R
0 if r> R

where r is the distance from the origin. Its eigenfunctions psi(r) are governed by

\frac{\hbar^2}{2m} \nabla^2 \psi + V(r) \psi = E \psi
ALL in spherical coords.

Consider a spherically symmertic eigenfunction with no angular dependence of the form

\psi(r) = \frac{u(r)}{r}

Solve for u(r) in teh regions r< R and r > R and yb imposiing boundary conditions, find the eigenfunction of a bound state with energy E = \hbar^2 \alpha^2 / 2m

Show taht there is one bound state of this kind if the depth of the weel obeys
\frac{\hbar^2 \pi^2}{8mR^2} &lt; V_{0} &lt; \frac{9\hbar^2 \pi^2}{8 mR^2}

Homework Equations


Ok i found te solution of the wavefunction to be
C \sin (k_{0}r) /r if r < R
A e^{\alpha r}/ r if r > R
The solutions are such because the solutions are found a bound state that is E <= V0. Also the solutions are spherically symmetric.

where k_{0} = \sqrt{\frac{2m}{\hbar^2} (V_{0} + E)}

The Attempt at a Solution


Furthermore i found that
k_{0} \cot k_{0} R = -\alpha
k_{0}^2 + \alpha^2 = \frac{2m}{\hbar^2} V_{0}

How would i prove the condition for V0?? Would i do this graphically assuming different values for R?

Thanks for your help!
 
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