Boundary Layer Theory: Displacement & Momentum Thickness Explained

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Displacement thickness and momentum thickness are key concepts in boundary layer theory, representing the effects of the boundary layer on mass and momentum flow in viscous fluid flows. Displacement thickness quantifies how much the wall would need to be moved to maintain the same mass flow rate as in an inviscid case, while momentum thickness measures the impact on momentum flow. The divergence of streamlines away from the body in the boundary layer is necessary to conserve mass, as the presence of the boundary layer alters the flow characteristics. Both thicknesses are integral to understanding the behavior of boundary layers and are calculated using specific integrals. These concepts are crucial for analyzing viscous flows around surfaces.
mrajkumar
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Hi,
could you tell the physical meaning of the displacement and momentum thickness of a boundary layer.And why the stream line diverges away from the body in the boundary layer to conserve mass?
 
update - I wan't sure about what you meant by momentum thickness, but thanks to boneh3ad's next post, it's explained there.

Link to flat plate article:

flat plate.htm
 
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The convexity or concavity of the surface is irrelevant for the question at hand, and by stating that this is a question about boundary layers automatically means this is a viscous flow.

The displacement thickness (##\delta_1## or ##\delta^*##) is a measure of the effect of the boundary layer on the flow of mass in a fluid. Essentially, you can solve the flow inviscidly and come up with a certain overall mass flow rate. Then solve the same flow accounting for the boundary layer, and the mass flow will be slightly smaller. The displacement thickness is the distance the surface would have to be displaced in order that the mass flow in the inviscid case would be the same as that in the viscous case with the original wall position. In essence, it is the distance the wall must move in order to get the same outer flow (inviscid) answer without solving for the boundary layer.

\delta^* = \int\limits_0^{\infty}\left(1 - \dfrac{u}{U_{\infty}}\right)dy.

The momentum thickness (##\delta_2## or ##\theta##) is similar, only it deals with the flow of momentum rather than mass. It shows up in the momentum integral boundary layer equation (as does ##\delta^*##).

\theta = \int\limits_0^{\infty}\dfrac{u}{U_{\infty}}\left(1 - \dfrac{u}{U_{\infty}}\right)dy
 
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