Box Acceleration with Given Force and Coefficient of Friction

AI Thread Summary
To determine the acceleration of a 15.0 kg box being pushed with a force of 72.0 N at a 65-degree angle, the net force acting on the box must be calculated using the equation Fnet = ma. A force diagram should be drawn to visualize all forces, including the applied force and frictional force, which is influenced by the coefficient of friction of 0.12. The vertical component of the applied force and the normal force must also be considered to find the frictional force. Once the net force is established, the acceleration can be calculated by rearranging the formula to solve for 'a'. Understanding these concepts is crucial for solving the problem effectively.
RajNijhar
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Homework Statement


A person is pushing a 15.0kg box on the ground with a force of 72.0N 65Degrees from the horizontal. if the coefficient of friction is0.12 what will be the acceleration of the box?


Homework Equations


Fnet=ma
theres other formulas but i don't have my data sheet :(


The Attempt at a Solution


soo lost don't even know where to start pelase help
 
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That is the only major equation you need to solve the problem.
 
Draw a force diagram , showing all forces acting on the box.

p.s. welcome to Physics Forums, everybody. :smile:
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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