Box and friction distance problem?

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A box sliding up a 17.0° incline with an initial speed of 1.30 m/s experiences kinetic friction with a coefficient of 0.180. The problem requires calculating how far the box travels before coming to rest, considering both gravitational and frictional forces acting against its motion. To solve, one must determine the normal force, calculate the frictional force, and find the net acceleration. The kinematic equation V^2 = v_0^2 + 2as can then be applied, where V is zero when the box stops. This approach will yield the distance traveled along the incline before the box comes to rest.
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Homework Statement


A box is sliding up an incline that makes an angle of 17.0° with respect to the horizontal. The coefficient of kinetic friction between the box and the surface of the incline is 0.180. The initial speed of the box at the bottom of the incline is 1.30 m/s. How far does the box travel along the incline before coming to rest?



Homework Equations


Ffr=(mu)(FN)



The Attempt at a Solution


I tried drawing a free body diagram and altering my x-axis to the incline but I can't seem to figure it out. Any help would be greatly appreciated. THanks!
 
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Hi there!
It could always help, on your part, to post the drawings/sketches you've already made, so that one gauge where you stand...
Anyhow, you must notice that, as the box struggles against the incline, it is opposed by both gravity, and friction.
You must first find the normal force from the surface, and determine the friction, add to that the component of gravity resisting its movement, and that will be your acceleration.
Kinematics then leads to:
<br /> \large <br /> V^2 = {v_0}^2 + 2as<br />
Where you seek- S, and V is known to be zero, when the object stops.
Try it,
Daniel
 
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