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ti-84minus
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Homework Statement
In the game of bridge, four players are dealt 13 cards each from a well-shuffled deck of 52 playing cards. What is the probability that one of the players holds a hand that is made up of only one suit?
Homework Equations
nCr = n!/(r!(n-r)!)
The Attempt at a Solution
I know that when 1 player is dealt all of one particular suit, it should be 4/52C13
But for some reason, the answer at the back of the book for this question is very strange:
([(42*39!)/(13!3*3!) - (62*26!)/(13!2*2!) + 24] / (52!/(13!4*4!)
and this isn't equal to 4/52C13...
Since I already have the answer, I would like a thorough explanation of why it is so...
Thanks a lot!
:)