(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In the game of bridge, four players are dealt 13 cards each from a well-shuffled deck of 52 playing cards. What is the probability that one of the players holds a hand that is made up of only one suit?

2. Relevant equations

_{n}C_{r}= n!/(r!(n-r)!)

3. The attempt at a solution

I know that when 1 player is dealt all of one particular suit, it should be 4/_{52}C_{13}

But for some reason, the answer at the back of the book for this question is very strange:

([(4^{2}*39!)/(13!^{3}*3!) - (6^{2}*26!)/(13!^{2}*2!) + 24] / (52!/(13!^{4}*4!)

and this isn't equal to 4/_{52}C_{13}...

Since I already have the answer, I would like a thorough explanation of why it is so...

Thanks a lot!

:)

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# Homework Help: Bridge Probabilities exactly 1 person with 1 suit?

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