Buckingham Pi / Dimensional analysis

beth92
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Homework Statement



A capillary filled with water is placed in a container filled with a chemical of concentration C_{0}, measured in number of molecules per unit volume. The chemical diffuses into the capillary of water according to the following relation (where x is distance along capillary):

\frac{\partial C}{\partial t} = D \frac{\partial^{2}C}{\partial x^{2}} ~~~~ C(0,t) = C_{0} ~,~ C(x,0)=0

a) Find dimensions of diffusion coefficient D
b) For capillary with cross sectional area A, the number of molecules entering the capillary N in a fixed time T is measured. We can assume that there is a law relating the 5 quantities D, C_{0}, N, T, A. Use dimensional analysis to find the general form of this law.
c) If experiments show that N is proportional to \sqrt{T}, then give the simplest law which expresses N as a function of the 4 other quantities.

Homework Equations



Buckingham Pi theorem says that the law will have the form F(\pi_{1},\pi_{2},...) = 0 where the \pi_{i} are dimensionless quantities created using the 5 given physical quantities.

The Attempt at a Solution



a) I calculate the dimensions of D to be L2/T

b) I calculate my dimensionless quantities as:

<br /> <br /> \pi_{1} = N \\<br /> <br /> \pi_{2} = A^{3}C_{0}^{2} \\<br /> <br /> \pi_{3} = \frac{T D}{A}<br /> <br />

c) This is the part I'm not sure of. What does it mean by the 'simplest' law? From the buckingham Pi theorem I get that:

N = g( A^{3}C_{0}^{2},\frac{TD}{A} )

Where g is some unknown function.

But I'm not sure what to do with the fact that N varies with the square root of T. Can I take that term out and say:

N = \sqrt{\frac{TD}{A}} f(A^{3}C_{0}^{2})

This doesn't seem right/complete to me but I can't think of anything else.
 
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beth92 said:
But I'm not sure what to do with the fact that N varies with the square root of T. Can I take that term out and say:

N=TDA‾‾‾f(A3C20) N = \sqrt{\frac{TD}{A}} f(A^{3}C_{0}^{2})

This doesn't seem right/complete to me but I can't think of anything else.


Yes, you can do this. If ##f## would depend on ##\pi_3##, then ##N## would not vary as ##\sqrt{T}##.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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