Buckling Load Equation for Eccentrically Loaded Rectangular Solid Column

mhajinaw
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Homework Statement


I'm reading a paper and I'm trying to understand how does the author arrived from equation (1) to the following buckling load equation (2). I know that the author substitutes equation (1) with the dimensions of the geometry but I still could not understand how he comes to last term 6e/t in equation (2).
Geom.PNG

Homework Equations


P=Aσmax / [1+ec/r2] (1)

P=Btσy / [1+6e/t] (2)

where;
A=cross-sectional area of column
e=eccentricity
B,t=geometry of specimen (refer to attached figure)
c= distance from neutral axis to the outer fiber where σmax occurs
r, radius of gyration, r2=I/A where I is the moment of inertia computed about the bending axis

The Attempt at a Solution


I tried to play around by substituting r2 with I/A. But I don't know how can I expand the results afterwards. Maybe there are some simplifications that I missed.
 
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mhajinaw said:

Homework Statement


I'm reading a paper and I'm trying to understand how does the author arrived from equation (1) to the following buckling load equation (2). I know that the author substitutes equation (1) with the dimensions of the geometry but I still could not understand how he comes to last term 6e/t in equation (2).
View attachment 111853

Homework Equations


P=Aσmax / [1+ec/r2] (1)

P=Btσy / [1+6e/t] (2)

where;
A=cross-sectional area of column
e=eccentricity
B,t=geometry of specimen (refer to attached figure)
c= distance from neutral axis to the outer fiber where σmax occurs
r, radius of gyration, r2=I/A where I is the moment of inertia computed about the bending axis

The Attempt at a Solution


I tried to play around by substituting r2 with I/A. But I don't know how can I expand the results afterwards. Maybe there are some simplifications that I missed.
The first equation represents loading on a relatively short eccentric/ compression loaded column; the second appears to be that same formula when the max stress reaches yield on a eccentrically loaded rectangular solid column of width B and depth t (found by replacing c with t/2, the distance from section centroid to outer fiber, and by replacing r^2 with I/A, where I is Bt^3/12, and A is Bt). That's the only sense I can make of the 2nd equation.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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