A wooden block of mass M = 1.83 kg is rest on a frictionless, horizontal table attached to the end of an unstretched spring (k = 217 N/m). A bullet of mass m = 8.02 g is fired horizontally into the block at speed vo = 394 m/s. The bullet comes to rest inside the block, and causes the mass to oscillate on the spring. If there is no friction between the block and the table: find A, the amplitude of the resulting oscillation. You can assume the mass never hits the wall (to which the spring is attached.) Here is what I did, and I really don't see how this is wrong... By conservation of momentum --> m1v1 = (m1 + m2)v2 (.0082)(394) = (1.83 + .0082)v2 v2 = 1.75759m/s 1/2mv^2 = 1/2kA^2 (1/2)(1.83802)(1.75759)^2 = (1/2)(217)A^2 A = .162m How is this wrong??