Bungee Jumper Oscillation: Determine Spring Constant

Thread starter lindsk
Start date Nov 15, 2009
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Bungee Constant Oscillation Spring Spring constant

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To determine the spring constant of the bungee cord, the oscillation period of the jumper is essential. The jumper, with a mass of 87 kg, oscillates up and down, completing two cycles in 8.5 seconds, indicating a period of 4.25 seconds per cycle. Using the formula for the period of a mass-spring system, T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant, the spring constant can be calculated. Rearranging the equation to solve for k gives k = (4π²m)/T². This calculation leads to the determination of the bungee cord's spring constant, providing insights into the dynamics of bungee jumping.

Nov 15, 2009

lindsk

A bungee jumper, whose mass is 87 kg, jumps from a tall platform. After reaching his lowest point, he continues to oscillate up and down, reaching the low point two more times in 8.5 s. Ignoring air resistance and assuming that the bungee cord is an ideal spring, determine its spring constant.

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Nov 16, 2009

ideasrule

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What do you think? Can you show us all relevant equations as well as your attempted solution?

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