By using binomial distribution if two coin are tossed 4 times ,find?

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Homework Help Overview

The discussion revolves around a problem involving the binomial distribution, specifically related to tossing two coins four times. Participants are exploring various probabilities and statistical measures associated with the outcomes of these tosses.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to calculate probabilities for specific outcomes, such as the number of heads and tails in multiple tosses. Questions are raised regarding the interpretation of the problems, particularly about the definitions of the events being analyzed.

Discussion Status

The discussion is ongoing, with some participants providing initial calculations and others seeking clarification on the problems. There is a mix of attempts to solve the first problem and requests for guidance on how to proceed with the calculations.

Contextual Notes

Participants are encouraged to show their work and clarify their understanding of the problems. There is an emphasis on self-solving, with some constraints on providing direct solutions.

mattamimi
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by using binomial distribution if two coin are tossed 4 times ,find?
1)the probability of 2 heads in 4 times ?
2)the probability of less than one head once?
3)the probability of than 2 tails in 3 times ?
4)the expected number of two tails ?
5)the variance of the number of 2 heads?
 
Last edited by a moderator:
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Welcome to PF!

Hi mattamimi! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help …

start with 1). :smile:
 
thank you :)


1.) I think P(x)=4C1*(1/4)^1*(3/4)^3=0.421
 
mattamimi said:
1.) I think P(x)=4C1*(1/4)^1*(3/4)^3=0.421

(try using the X2 tag just above the Reply box :wink:)

uhh? that's obviously the probability of one head in 4 times
 
sorry,but I couldn't solve it,can you solve the first problem
 
Sorry, but you have to do it yourself.

Please can I check that I understand 1) correctly …

is 1) asking for the probability that when 2 coins are tossed 4 times, there will be 2 heads 4 times, ie a total of 8 heads, ie all heads?

And is 2) asking for the probability that there will be 2 tails exactly once (so the other three times are either 2 heads or one of each)?

And what is the missing word in 3)?
 
Moderator's note: thread moved from "Set Theory, Logic, Probability, Statistics"
 
mattamimi said:
...can you solve the first problem

I think I speak for tiny-tim as well as for myself:
"YES".

Just to clarify, you are flipping two coins and recording the number of heads. Then you repeat this until you have FOUR numbers?
 

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