Calaculate Mass of Cube submerged in oil and water

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Homework Help Overview

The problem involves calculating the mass of a cube submerged in two fluids: oil and water. The cube has specific dimensions and is partially submerged, with the oil layer on top and water below. Participants discuss the pressures acting on the cube and the application of Archimedes' principle.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the use of Archimedes' principle to find the buoyant forces from both fluids and how they relate to the weight of the cube. There are attempts to calculate forces based on pressure and area, with some questioning the correctness of their calculations.

Discussion Status

Some participants have provided guidance on using Archimedes' principle separately for each fluid. There is a mix of interpretations regarding the calculations of forces and pressures, with one participant expressing confusion about their results. A participant claims to have arrived at the correct mass after further discussion.

Contextual Notes

Participants mention the use of gauge pressures and refer to previous calculations being marked correct in a physics mastering system. There is an ongoing discussion about the assumptions made regarding the pressures and the method of calculation.

TFM
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[SOLVED] Calaculate Mass of Cube submerged in oil and water

Homework Statement



A cube is submerged in water and oil the oil is on top, and forms a layer 10cm thick. the water is underneath and forms another layer 10cm thick. the cube has sides of 10.2cm, and has 2.3cm below the oil water line. the density of the oil is 790kg. I have worked out already the force on the top of the cube is 163 Pa, and on the bottom 1000 Pa. How do you work out the mass of the cube?

Homework Equations



Pressure = Force/Area

Archimedes: The upward force is equal to the weight of fluid displaced by the block (?)

The Attempt at a Solution



Any help would be appreciated

TFM
 
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Use Archimedes' separately for the two parts submerged in the two liquids and add the buoyant forces to balance the weight. Hence, find mass. No need to find pressure.
 
Am I doing simetghing wrong? I am doing:

F = p*A
A = 0.102^2 = 0.0104

P top = 163
Pressure Bottom = 1000

F top:1.696
F bottom = 10.404
Sum F = 12.10

using F = mg,

m = 1.23kg

But it is wrong?

TFM
 
TFM said:
Am I doing simetghing wrong? I am doing:

P top = 163
Pressure Bottom = 1000

TFM

Show how you got these two.
 
Therehave been stated as being right, because I am using mastering physics, and have previously calculated them and got them marked correct.

I used P = denstiy*g*height,
Density Oil = 790 (stated in question)
height I calculated as being 2.1cm (0.021m)

Works out as 163 Pa (Did same thing for Water at the bottom, but used the total pressure = pressure caused by the oil on top + the pressure from the water layer from the join to the bottom of the cube.)

The Pressures are gauge pressures, by the way, if that helps?

TFM
 
Last edited:
TFM said:
Am I doing simetghing wrong? I am doing:


F top:1.696
F bottom = 10.404
Sum F = 12.10

using F = mg,

m = 1.23kg

But it is wrong?

TFM

Why have you added the forces? Net force acting upward should be F_bottom - F_top.

I still recommend that you learn how to solve using the method I had told you right in the beginning. If the body given is not a cube or parallelepiped, then you won't be able to do it using your way.
 
Thanks. Finally got the right answer (0.889kg)

TFM
 

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