Calc Density Unknown Liquid: Buoyancy & Tension | Fluid Physics

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To determine the density of the unknown liquid, the buoyant force acting on the submerged styrofoam block must be calculated using the equation that incorporates both the weight of the block and the tension in the rope. The block's volume is 5.00 cm³ and its density is 45 kg/m³, allowing for the calculation of its mass. The tension in the rope, measured at 3.63 x 10^-2 N, must be included in the force balance equation. The correct formulation is buoyant force equals the weight of the block plus the tension, leading to the equation: density of the liquid times volume times gravity equals mass times gravity plus tension. This approach will yield the density of the unknown liquid.
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A styrofoam block with a volume of 5.00cm cubed and a density of 45 kg/m cubed is submerged in an unknown liquid tethered from floating to the surface by a rope fixed to the bottom of the container. the tension in the rope measures 3.63x10^-2 N. Determine density of unknown liquid.

I set buoyant force equal to mass x gravity since the styrofoam would be at the surface if not for the rope and substituted in density x gravity x volume of water for buoyant force but i think i am doing something wrong. Can anyone help?
 
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Include the tension of the rope in the force balance.
 
ok. so buoyant force=mg-tension, and then density x volume x gravity= m x g -T?

it dosent give the mass of the block though
 
buoyant force=mg+T
 
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