Calc Equilibrium Forces in Rigid Bodies

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To maintain equilibrium in a rigid body with multiple upward forces, the sum of these forces must equal the weight of the body, while the sum of torques must equal zero. For a table with three legs, the equations governing equilibrium can be established, but adding a fourth leg introduces an additional unknown without a corresponding equation. The fourth equation can be derived by considering the elasticity of the surface and the properties of the table legs. Advanced knowledge of plate theory is necessary to solve for the forces in this scenario. Understanding the interaction between the legs and the supporting surface is crucial for determining the force distribution.
hellknows2008
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Hi,

Given a rigid body, to keep the body equilibrium, multiple upward forces act on the body with each a known displacement from the center of mass. How can we calculate the upward forces?

Now imagine we have a table, with 3 legs of neglible mass, the center of mass is at the center of the table, the displacements of the table legs are known. To make the table in equilibrium, we have the following equations:

f0 + f1 + f2 = -fw (F0, F1 and F2 are upward forces acted by the table legs, FW is the weight of the table)
D0 x F0 + D1 x F1 + D2 x F2 = 0 (this is the sum of torques caused by forces acted by the table legs, D0, D1 and D2 are displacements from the center of mass of the table)
the above equation turns out to be: (assuming z-axis is the vertical axis)

[x0 y0 0]^T x [0 0 f0]^T + [x1 y1 0]^T x [0 0 f1]^T + [x2 y2 0]^T x [0 0 f2], then all together gives the following system of equations:

f0 + f1 + f2 = -fw
y0*f0 + y1*f1 + y2*f2 = 0
-x0*f0 - x1*f1 - x2*f2 = 0

We can solve the above by Gaussian elimination or matrix inversion.

The problem is, how can we generalize to handle more than 3 table legs?

With 4 legs, we have

f0 + f1 + f2 + f3 = -fw
y0*f0 + y1*f1 + y2*f2 + y3*f3 = 0
-x0*f0 - x1*f1 - x2*f2 + x3*f3 = 0

However, we only have 3 equations but we have 4 unknowns here

Thanks in advance for any help

vc
 
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There is no way to tell. You only need 3 points of support. A 4th one is a redundancy. Realistically, on a perfect surface, one of the legs is going to be a bit short, resulting in only 3 legs used for support. On a real surface, there will be a bit of a give, so all 4 legs may touch at once. Then the exact lengths of all 4 legs and elastic properties of the surface will determine the force distribution.

If you don't account for the properties of the surface, you can't resolve the problem. If you do, there is your missing 4th equation.
 
Thank you for your reply

So, with 4 legs of the same given length, and a given elasticity of the surface then, how do we come up with the 4th equation??

Thank you very much
 
It is a very difficult problem requiring advanced knowledge of plate theory, the solution of which depends on the degree of elasticity of the supporting surface, table legs, and table surface itself. See here for some info regarding its solution, but no solution is given.
https://www.physicsforums.com/showthread.php?t=138020
 
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