Calculalting displacement, distance and acceleration

AI Thread Summary
To find the distance traveled by an object on a velocity vs. time graph with a concave-up parabolic line, the distance is determined by calculating the integral of the velocity, which can be estimated using Riemann sums if only a graph is available. Instantaneous acceleration is found by taking the derivative of the velocity, representing the slope at any given point on the curve. Average velocity can be calculated by subtracting the initial velocity from the final velocity and dividing by the time interval. For a curved line, drawing a tangent at a specific point allows for determining the slope, which corresponds to instantaneous acceleration. Understanding these concepts clarifies how to analyze motion represented in velocity vs. time graphs.
doc.madani
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hello, i was wondering how i can find the distance traveled by an object in a velocity vs time graph, whilst the line being half a parabola concave up. Inregards to that how can i find acceleration and average velocity (just the formula's). i know in a constant velocity line acceleration is equal to acceleration, i just don't know how to find acceleration on a curved line. (just a gues, would you need to draw a tangent on a point of the line, and hence find the gradient of that line?)

thankyou :)
 
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doc.madani said:
hello, i was wondering how i can find the distance traveled by an object in a velocity vs time graph, whilst the line being half a parabola concave up.

The distance traveled will simply be the integral of the velocity. In the case where you only have a graph, you'll need to estimate the integral using say, Riemann sums.

doc.madani said:
Inregards to that how can i find acceleration and average velocity (just the formula's).

The instantaneous acceleration is simply the derivative of the velocity, that is the slope at any instance. The average velocity, is simply the final velocity - initial velocity divided by the time interval.

doc.madani said:
i know in a constant velocity line acceleration is equal to acceleration, i just don't know how to find acceleration on a curved line. (just a gues, would you need to draw a tangent on a point of the line, and hence find the gradient of that line?)

acceleration is equal to acceleration? The instantaneous acceleration of any point is the slope of the line at that point.
 
Pengwuino said:
acceleration is equal to acceleration? The instantaneous acceleration of any point is the slope of the line at that point.

my bad i was meant to say acceleration is equal to the slops, thank you i have a good understanding now :)
 
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