Calculate 8000 Megajoules of Water Tunnel Kinetic Energy

AI Thread Summary
The discussion focuses on calculating the kinetic energy of water in a 14 km tunnel with a diameter of 7.7 m and a flow speed of 3.75 m/s, which totals approximately 8000 Megajoules. The relevant equation for kinetic energy (KE) is KE = 0.5 * m * v^2, where m is the mass of the water and v is the velocity. Participants are encouraged to show their calculations and cite sources, adhering to forum rules. The conversation emphasizes the importance of understanding the principles behind the calculations. Ultimately, the goal is to verify the energy value through proper application of the kinetic energy formula.
AslamRandhawa
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There is 14 km of tunnel of 7.7 m diameter, full of water traveling at 3.75 m/s,that represents approximately 8000 Megajoules of kinetic energy.

How? Calculate it to prove (Taken From Wikipedia under topic of "Water Hammer".
 
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This is the homework section of the forum. Forum rules require you to use the homework template, cite any relevant equations and attempt to solve it yourself before help is given.

What's the usual equation for KE?
 

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