Calculate Acceleration Given V0 and X

  • Thread starter Thread starter LiiArch
  • Start date Start date
  • Tags Tags
    Acceleration
AI Thread Summary
The astronaut on planet Zog kicks a football with an initial velocity of 11.7 m/s, achieving a maximum distance of 90 m. To find the acceleration due to gravity (g), he calculates the optimal launch angle, which is 45 degrees, resulting in horizontal and vertical components of 7.78 m/s each. Using these values, he determines the time of flight to be approximately 11.6 seconds. Initially, he miscalculated the initial velocity, which affected his results, but after correcting it, he successfully finds g to be 1.34 m/s². This example illustrates the importance of accurate initial conditions in projectile motion calculations.
LiiArch
Messages
10
Reaction score
0

Homework Statement


An astronaut kicks a football on a level area of planet Zog. He kicks the ball repeatedly at a wide range of angles from nearly zero to almost 90 deg above the horizontal, but always as hard as he can which gives an initial velocity of 11.7 m/s. The astronaut notices that the maximum distance the ball lands away from him is 90 m. Armed with this information and because he mastered Physics 2048, he returns to his landing craft and quickly calculates the acceleration of gravity g on planet Zog. What is that value?

V0 = 11.7 m/s
X = 90 m
X0 = 0 m
Y0 = 0 m

All of the relevant equations I think I can use involve time, which is not given. So, I do not know where to begin. If I can figure out where to start, I think I can figure it out pretty easily.
 
Physics news on Phys.org
At what angle will the ball travel the maximum distance?

Think about that. The rest of the problem should follow naturally.
 
You have to go a little bit outside of plugging values into the kinematic equations.

Hint: The maximum distance the ball goes is 90m.

EDIT: Sid beat me to it.
 
Okay, that did get the ball rolling. I figured it was 45.0 degrees, so I calculated Vx and Vy.

Vx = 7.78 m/s
Vy = 7.78 m/s

Then I plugged in these values to this equation to find t:

X(t) = X0 + Vx0t
90 = 0 + 7.78t
11.6 s = t

So then I plug t = 11.6 s into this equation:

Y(t) = Y0 + Vy0t - 1/2(g)(t^2)
0 = 0 + 7.78(11.6) - 1/2(11.6^2)(g)
0 = 90.25 - 67.28g
67.28g = 90.25
g = 1.34 m/s^2

But, this is incorrect. :[
 
Are you sure you calculated the initial velocities correctly?
 
No I just realized that. For some reason I was putting 11 instead of 11.7 - silly me.

With new numbers, I got it right. Thanks guys!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top