Calculate Angular Velocity of a Diver in Tuck Position

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The discussion focuses on calculating the angular velocity of a diver transitioning from a straight position to a tuck position, utilizing the conservation of angular momentum principle. The diver completes 2.00 rotations in 1.33 seconds, indicating a final angular velocity of approximately 4.73 rad/s in the tuck position. Given that the rotational inertia decreases by a factor of 3.00, the initial angular velocity when leaving the diving board is determined to be 3.15 rad/s. The equation I1W1 = I2W2 is essential for solving this problem.

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A diver can change his rotational inertia by drawing his arms and legs close to his body in the tuck position. After he leaves the diving board (with some unknown angular velocity), he pulls himself into a ball as closely as possible and makes 2.00 complete rotations in 1.33 s. If his rotational inertia decreases by a factor of 3.00 when he goes from the straight to the tuck position, what was his angular velocity when he left the diving board?

1. 3.15 rad/s
2. 3.05 rad/s
3. 2.85 rad/s
4. 3.25 rad/s




I know that i am supossed to use this equations I1W1=I2W2, but i am not getiing on of these answers at all and i don;t know what i am doing wrong.
 
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Works fine for me. What do you get for the angular velocity when he's a ball?
 
lol nevermind, i flipped the numbers.
thanks
 

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