Calculate Charge: Find Q at Center of Hollow Sphere of Radius 20 cm

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The discussion centers on calculating the unknown charge Q located at the center of a hollow conducting sphere with a radius of 20 cm. The electric field just outside the sphere is initially 500 N/C, which indicates the charge on the conducting shell. When an unknown charge Q is introduced at the center, the electric field decreases to 100 N/C while still pointing outward. Participants suggest applying Gauss's law to determine how the net charge within the Gaussian surface changes due to the presence of Q. Ultimately, the problem is clarified, leading to a better understanding of the charge dynamics involved.
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The e-field just outside the surface of a hollow conducting sphere of radius 20 cm is 500 N/C and is directed outward. Q is located at the center of the sphere. It is noted that the e-fields is still directed out ward with a magnitude of 100 N/C. What is the magnitude and sign of the unknown charge Q?

I can only find total charge which is 2.225nC. I can't get Q coz radius of the solide sphere is unknown. Pls help
 
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Can you please state the problem completely, exactly as it was given. I don't understand what the field 100 N/C refers to.
 
The electric field just outside the surface of a hollow conducting sphere of radius 20 cm is 500 N/C and is directed outward. An unknown charge Q is then located at the center of the sphere. It is noted that the electric field is still directed outward but its magnitude has decreased to 100 N/C. What is the magnitude and sign of the unknown charge Q?

This is the complete question as it is stated.
 
austin007 said:
The electric field just outside the surface of a hollow conducting sphere of radius 20 cm is 500 N/C and is directed outward.
OK. That should tell you the charge on the conducting shell.
An unknown charge Q is then located at the center of the sphere.
Ah... that additional word "then" makes all the difference!
It is noted that the electric field is still directed outward with a magnitude of 100 N/C.
Now that you've added charge Q, how does the net charge within the gaussian surface (taken just outside the sphere) change?

Apply Gauss's law twice.
 
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thanks I understood finally...
 
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