Calculate Contact Force: Car and Truck Collision on Icy Road

AI Thread Summary
The discussion centers on calculating the contact force between a car and a truck involved in a collision on an icy road. Given the car's mass of 850 kg and the truck's mass of 3550 kg, the car exerts a force of 156671 N on the truck 60 ms after the collision. Using the equation for acceleration and Newton's third law, the contact force on the car due to the truck is calculated to be 12640 N. The participants express a mix of relief and humor about the simplicity of the calculation. Overall, the thread emphasizes the application of fundamental physics principles in collision scenarios.
ttk3
Messages
27
Reaction score
0

Homework Statement



A car of mass 8.50E+2 kg and a truck of mass 3.55E+3 kg run into one another due to ice on the road. 60.0 ms after the collision, the car is pushing on the truck with a force whose magnitude is 1.56671E+5 N. Calculate the size of the force on the car due to the truck at that time.


Homework Equations



accel. of car = accel. of truck
a = f / sum of masses
Contact force = mass of truck * (f/sum of masses)


The Attempt at a Solution



contact force = 3550 * (15667 / [850 + 3550])

= 12640 N
 
Physics news on Phys.org
Consider Newton's 3rd law.
 
That was too easy. Haha, I feel stupid.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top