Calculate Derivative of a function

jweber
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Calculate the derivative of the function

g(z) = ((9z^2)/(6+z))^2

Find g'(z) =

Also Calculate dy/dx of the following function

y= (6x^2+x) (4x-x^2)

You do not need to expand answer.

Any help is greatly appreciated thank you.


Homework Equations





The Attempt at a Solution

 
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We don't do your homework for you, we help you with it. Now, what have you tried so far on the first one? Quotient rule seems to be the obvious choice...
 
Also Calculate dy/dx of the following function

y= (6x^2+x) (4x-x^2)

Ok, I can give you some hints with this one.

You have two options:

1. Multiply (6x^2+x) (4x-x^2) out then take the derivative.

2. Use product rule

Hint for product rule let f(x)=(6x^2+x) and g(x)=(4x-x^2) then use the following formula

(dy/dx)=f '(x)g(x) + f(x)g '(x)

The first option may sound like the easy way out but don't depend on it completely.

What if you had to find (dy/dx) of y=(x^2)(Ln(x))

Now you have no choice but to use the second option and the formula.

Also, I would like for you to actually know what a derivative is.

What is a derivative? You need to know this.

I'm going to say it right here so NEVER forget it.

A derivative is the instantaneous slope on a graph at a specific point.

There are other explanations but at least know that one.

We also need to talk about (dy/dx)

What does (dy/dx) mean?

You can read it as the derivative of y with respect to x.

(dy/dx) is actually an implicit differentiation.

And don't forget that you can also call (dy/dx) as y '
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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