Calculate differential equation

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Homework Help Overview

The discussion revolves around a differential equation given by y=xy'-(y')^2. Participants are exploring methods to analyze and solve this equation, which involves derivatives and potentially second-order terms.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants express uncertainty in their initial attempts, with one suggesting a substitution that complicates the equation further. Another participant differentiates both sides and raises the need to verify solutions of the resulting second-order ODE. There is also a discussion about potential linear solutions and conditions that must be satisfied for these to hold.

Discussion Status

The conversation includes attempts to derive solutions and check their validity. Some participants have provided insights into the structure of the equation and possible forms of solutions, while questions about restrictions on constants in the solutions remain open.

Contextual Notes

Participants are navigating the complexities of the differential equation without a clear consensus on the best approach or solution. The discussion reflects various interpretations and methods being considered.

Chromosom
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Homework Statement



[tex]y=xy^\prime-\left(y^\prime\right)^2[/tex]

Homework Equations





The Attempt at a Solution



Unfortunately, I do not have any good idea. I tried [tex]y=xt(x)[/tex], but the equation only became worse.
 
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Chromosom said:

Homework Statement



[tex]y=xy^\prime-\left(y^\prime\right)^2[/tex]

Homework Equations





The Attempt at a Solution



Unfortunately, I do not have any good idea. I tried [tex]y=xt(x)[/tex], but the equation only became worse.

Differentiate both sides with respect to [itex]x[/itex]. You do have to check whether all the solutions of the resulting 2nd order ODE are solutions of this ODE.
 
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Very clever :)

[tex]y^\prime=y^\prime+xy^{\prime\prime}-2y^\prime y^{\prime\prime}[/tex]

[tex]xy^{\prime\prime}-2y^\prime y^{\prime\prime}=0[/tex]

[tex]y^{\prime\prime}\left(x-2y^\prime\right)=0[/tex]

Now we could expect that [tex]y=ax+b[/tex], but:

[tex]y^\prime=a[/tex]

[tex]ax+b=ax-a^2[/tex]

[tex]b+a^2=0[/tex]

The last equation must be satisfied in order to be a solution. And of course second solution: [tex]y=\frac{x^2}{4}+C[/tex]

Is it good answer?
 
Chromosom said:
Very clever :)

[tex]y^\prime=y^\prime+xy^{\prime\prime}-2y^\prime y^{\prime\prime}[/tex]

[tex]xy^{\prime\prime}-2y^\prime y^{\prime\prime}=0[/tex]

[tex]y^{\prime\prime}\left(x-2y^\prime\right)=0[/tex]

Now we could expect that [tex]y=ax+b[/tex], but:

[tex]y^\prime=a[/tex]

[tex]ax+b=ax-a^2[/tex]

[tex]b+a^2=0[/tex]

The last equation must be satisfied in order to be a solution.

This is correct.

And of course second solution: [tex]y=\frac{x^2}{4}+C[/tex]

Is there any restriction on the value of [itex]C[/itex]?
 

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