Calculate Dog's Displacement on Frozen Pond | Kinematics Example Problem

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The problem involves calculating the displacement of a 7.50 kg dog sliding on a frictionless pond, initially moving at 4.31 m/s along the x-axis while being pushed by a 16.1 N wind force in the y-direction. The equations for displacement in both x and y directions are discussed, emphasizing the need to account for different initial velocities and accelerations for each component. The correct approach involves using the kinematic equations for both axes separately, as the total displacement is not simply the sum of the x and y components. Participants highlight the importance of accurately determining initial values and accelerations to solve the problem correctly. Understanding these principles is crucial for calculating the dog's total displacement after 2.55 seconds.
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Don't know what I am doing wrong

An adventurous dog 7.50 kg dog runs onto a frozen, frictionless pond with an initial velocity of 4.31 m/s along the positive x-axis. The dog slides across the ice while being pushed by a steady wind with a force of 16.1 N in the positive y-direction. What is the magnitude of the dog's displacement (relative to where he came onto the ice) after 2.55s?

Can't I just use, Xf=Xi + Vixt + 0.5a(t^2) and Yf=Yi + Viyt + 0.5a(t^2)
 
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post a little more work, maybe.

x(t) is simple and uses one term.
y(t) is same, but diff terms.

displacement is not x(t)+y(t), however, in case that's what was assumed.
 
macgirl06 said:
Can't I just use, Xf=Xi + Vixt + 0.5a(t^2) and Yf=Yi + Viyt + 0.5a(t^2)
Sure. That will give you the components of the displacement, if you use the correct initial values and accelerations. What did use? Hint: Each component has a different acceleration and initial speed.
 

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