Calculate Electric Field at the Center of Semicircular Loop

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To calculate the electric field at the center of a semicircular loop with radius a and uniform positive charge Q, start by dividing the loop into differential charge elements dq. Each dq can be expressed in terms of the angle dθ, allowing for integration over θ to find the net electric field at point P. Due to symmetry, the horizontal components of the electric field will cancel out, leaving only the vertical components to consider. Set up the problem in a coordinate plane with point P at the origin and use trigonometric relationships to express the electric field components. The final expression for dq can be derived using the linear charge density, λ, defined as Q divided by the loop's length.
kjintonic
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A semicircular loop of radius a carries positive charge Q distributed uniformly over its length.?
Find the electric field at the center of the loop (point P in the figure). Hint: Divide the loop into charge elements dq as shown in the figure, and write dq in terms of the angle d\theta. Then integrate over \theta to get the net field at P.


http://i533.photobucket.com/albums/ee336/shaneji_kotoba/RW-20-72.jpg

I don't know how to start this question...
 
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kjintonic said:
A semicircular loop of radius a carries positive charge Q distributed uniformly over its length.?
Find the electric field at the center of the loop (point P in the figure). Hint: Divide the loop into charge elements dq as shown in the figure, and write dq in terms of the angle d\theta. Then integrate over \theta to get the net field at P.


http://i533.photobucket.com/albums/ee336/shaneji_kotoba/RW-20-72.jpg

I don't know how to start this question...
You must have some idea how to start, have you tried using the hint?
 
Probably I can use E= (S)dE= (S)kdq/r^2 inwhich r=a
(S) is integral sign
 
kjintonic said:
Probably I can use E= (S)dE= (S)kdq/r^2 inwhich r=a
(S) is integral sign
You're on the right lines, how about writing dq in terms of d\theta?

HINT: Notice that the horizontal components will cancel so you need only consider the vertical components of the electric field.
 
hmmm... Sorry I kinda don't understant how to write dq in terms of dd\theta:(
 
bump?
 
First step you should note that by symmetry, one of field components in an axial direction is 0. Now you only have to find the other component. Set this problem up in the coordinate plane with point P at the origin. Draw a triangle for E in terms of E_x and E_y and theta. What can you say about how E_x is related to x? Write down the expression for dE, the differential electric field magnitude due to dq, then try to write dq in terms of \lambda dr, where lambda is Q/length.
 
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