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Calculate equivalent resistor

  1. Jun 16, 2013 #1
    1. The problem statement, all variables and given/known data
    X7CzNJC.png

    Calculate equivalent resistor
    3. The attempt at a solution
    Req=(10 series 5)//(10)//(3)//(2)//(9 series 40) series 8//(4)

    I am not sure in the bolded text, is 9Ω connected serially with 40Ω.
     
  2. jcsd
  3. Jun 16, 2013 #2

    gneill

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    Staff: Mentor

    Nope. Redraw your circuit after performing the "(10 series 5)//(10)//(3)//(2)" operations.
     
  4. Jun 16, 2013 #3

    Simon Bridge

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    Do it yourself and see.
     
  5. Jun 17, 2013 #4
    As said above, redraw the circuit. You have the equivalent resistance of the unbolded text correct. redraw the circuit and you should see it is similar to what you have already done.
     
  6. Jun 18, 2013 #5
    First : [(10 series 5)//(10)//(3)//(2)] series 9 = 10Ω
    Redraw the circuit
    WpS4S0j.png
    Req = (40//10) series 4 series 8 = 20Ω
     
  7. Jun 18, 2013 #6

    gneill

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    Staff: Mentor

    Yup. Looks good.
     
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