ayae
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I'm a little stuck, how can I go about calculating the gravitational field on the surface of a mass in the shape of a torus using Gauss' Law.
That shape would not have enough symmetry to make using Gauss' law profitable.ayae said:I'm a little stuck, how can I go about calculating the gravitational field on the surface of a mass in the shape of a torus using Gauss' Law.
Doc Al said:That shape would not have enough symmetry to make using Gauss' law profitable.
I mean worth doing. Gauss' law always applies, but you can only use it to find the field in certain cases of high symmetry. (Such as spherical or cylindrical symmetry.)ayae said:When you say profitable, do you mean possible or worth while doing?
Step one is to find a gaussian surface with a uniform field. Can you do that for a torus?Because I really had my mind set on using Gauss' law for this example, is there no way of numerically calculating it?
This is what I feared, I didn't know whether it was symmetrical enough. Thanks for clearing it up.Doc Al said:I mean worth doing. Gauss' law always applies, but you can only use it to find the field in certain cases of high symmetry. (Such as spherical or cylindrical symmetry.)
Step one is to find a gaussian surface with a uniform field. Can you do that for a torus?
You'd need to use superposition, not Gauss' law.
Is the field strength constant over that center strip? Sure. But that's not a gaussian surface.ayae said:All I need to know is the gravitational acceleration at the very centre edge of the torus. So is it safe for me to make the assumption that g.n = g at this centre strip?
Sounds like you're still insisting on applying Gauss' law. You have to integrate over a closed gaussian surface, not just that center strip.And simplify down to g integral dA = 4 Pi G M, (which I can easily calculate).
Doc Al said:Is the field strength constant over that center strip? Sure. But that's not a gaussian surface.
Sounds like you're still insisting on applying Gauss' law. You have to integrate over a closed gaussian surface, not just that center strip.
Find the field contribution from each element of mass and add them up. Not trivial, I'm afraid.ayae said:If I can't find a gaussian surface for a which passes through the center strip what can I do? How would I do this using superposition?
I don't see any obvious way. You want the field at the inner edge, not along z.Can I not utilize the property of the torus being rotationally symetrical around z?
stevenb said:Just to through out a possible idea. Have you tried to use toriodal coordinates.
http://mathworld.wolfram.com/ToroidalCoordinates.html
http://en.wikipedia.org/wiki/Toroidal_coordinates
I haven't tried myself, but perhaps there is enough symmetry to apply Gauss's Law to a torus in this particular general curvilinear coordinate system.
Vanadium 50 said:Yes, but you will have to work out what the divergence operator is in toroidal coordinates. That may be non-trivial.
ayae said:This is what I feared, I didn't know whether it was symmetrical enough. Thanks for clearing it up.
You're going to have to forgive my scientific illilteracy, but I don't understand this.
All I need to know is the gravitational acceleration at the very centre edge of the torus. So is it safe for me to make the assumption that g.n = g at this centre strip? And simplify down to g integral dA = 4 Pi G M, (which I can easily calculate).
Exactly. (Still, non-trivial.)gabbagabbahey said:Personally, I wouldn't bother trying to find a Gaussian surface. Instead, just use Cartesian coordinates and find the contribution to the total field (at the field point you are interested in) by an arbitrary infinitesimal piece of mass on the toroid. Integrate over the entire toroid and you're done.