Calculate Heat Flows in Engines Propelling a Car

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To calculate the rate of heat flow into the engine, the kinetic energy required to propel a 1600 kg car to 22 m/s is determined to be 387200 J. Dividing this energy by the product of efficiency (23%) and time (9.7 s) yields a heat flow rate of approximately 199588 J/s. The discussion emphasizes the importance of conservation of energy in relating heat flow into and out of the engine. Participants seek clarification on how to approach the calculation for heat flow out of the engine. Overall, the conversation focuses on applying thermodynamic principles to solve the problem.
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Homework Statement


A certain engine can propel a 1600 kg car from rest to a speed of 22 m/s in 9.7 s with an efficiency of 23%.

what is the rate of heat flow into the engine at the high temperature?

what is the rate of heat flow out of the engine at the low temperature?

Homework Equations



e= 1- (Qout/ Qin)

The Attempt at a Solution



for the heat flow into the engine (high temp):
K= 0.5mv^2= (0.5)(1600)(22^2)= 387200 J

then I did 387200 J/ (0.23 x 9.7)= 199587.6289 J/s (not sure if this is correct)

I'm unsure as to how to do the second part of the question. Please help! Thanks :)
 
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Right so you have heat going in and work being done and heat going out.

So by conservation of energy what equation must relate these quantities??
 
I get it! thanks for your help :)
 
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