# Calculate magnetic field intensity

## Homework Statement

Two infinitely long filaments are placed parallel to the x-axis as shown in Figure 1.
a)Find H at the origin
b)Find H at (-1,2,2)

∫Hdl=Ienclosed
H=H1+H2

## The Attempt at a Solution

Well following the equation above I get Hl= Ienc then H1=Ienc/(2piRy) and H2=Ienc/(2piRz) then Ry=(0,0,0)-(0,4,0)=(0,-4,0) then length of Ry=4 and Rz=(0,0,0)-(0,0,4)=(0,0,-4) then Rz=4 thus H1=Ienc/(8pi) and H2=Ienc/(8pi) then H=H1+H2=10/(8pi)+10/(8pi)=20/(8pi)=.795 A/m that is for part a) I only listed this as I used the same method for part b) just with (-1,2,2) instead of (0,0,0)

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rude man
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## Homework Statement

Two infinitely long filaments are placed parallel to the x-axis as shown in Figure 1.
Figure 1?

whoops I was tired and forgot to add it

#### Attachments

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rude man
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Use Ampere's law: ∫H*ds = i. Which you did, sort of.

What you failed to do was to
(1) pay attention to the signs of Ienc y and Ienc z. The two currents are in opposite directions.

(2) compute Ry and Rz correctly. Given two points (x1 y1 z1) and (x2 y2 z2) what is the distance between them?

Last edited:
(x1,y1,z1)-(x2,y2,z2)=(x1-x2,y1-y2,z1-z2) then Ry=(0,0,0)-(0,4,0)=(0,-4,0)

right or no? I think that is what I did earlier uggg

rude man
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right or no? I think that is what I did earlier uggg
That's what you did, and it's wrong.

Check your analytic geometry text or the Web.

rude man
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(x1,y1,z1)-(x2,y2,z2)=(x1-x2,y1-y2,z1-z2) then Ry=(0,0,0)-(0,4,0)=(0,-4,0)
That's wrong. Furthermore, Ry is a distance and cannot be described by (x,y,z).

well I found a thing on euclidean distance Ry=sqrt((0-0)^2+(0-4)^2+(0-0)^2)=4

rude man
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well I found a thing on euclidean distance Ry=sqrt((0-0)^2+(0-4)^2+(0-0)^2)=4
Much better.

Ok so then Rz=sqrt((0,0,0)^2-(0,0,4)^2)=4 right?

Ah the directions are different one in into the page and one is out. I can't remember does x mean into the page or out of the page?

rude man
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Ah the directions are different one in into the page and one is out. I can't remember does x mean into the page or out of the page?
x is into the page and . is out of the page.

Ok so on the current is clockwise and on the dot current is counter clockwise so in the z direction it is negative and y it is positive

H=H1+H2=(10/2(pi)4)-(10/2(pi)4)=0

That doesn't seem right?

rude man
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Ok so then Rz=sqrt((0,0,0)^2-(0,0,4)^2)=4 right?
Right.

Ok well now that my distances are confirmed correct is my new answer correct?

rude man
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Ok so on the current is clockwise and on the dot current is counter clockwise so in the z direction it is negative and y it is positive
Currents don't run in circles. Currents run in the wires which are straight.

rude man
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H=H1+H2=(10/2(pi)4)-(10/2(pi)4)=0
No.
H is a vector, that's why I use bold type for it.

Take one wire at a time and determine the direction of H for it using your pix. You have the magnitudes right.

well it seems to be flowing into the page on the y axis and out of the page on the z axis. So on the y-axis the H vector would go left. Then I am guessing on the z axis since they are opposite the other H field must be to the right.

rude man
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well it seems to be flowing into the page on the y axis and out of the page on the z axis. So on the y-axis the H vector would go left. Then I am guessing on the z axis since they are opposite the other H field must be to the right.
Why left on the z axis? Do you know the right-hand rule?
Same comment for the z wire.
Draw circles around each wire intersecting with the origin, then use the rt-hand rule.

Well for the one into the page the B field will rotate clockwise and out of the page the B field will go counterclockwise. I said left and right because you have said something about the wires being straight and not circular so I guess I did not understand what you meant?

rude man
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Well for the one into the page the B field will rotate clockwise and out of the page the B field will go counterclockwise.
That is correct. So, taking the one into the page first, what direction does the H field point at the origin?

well since H is the magnetic field strength then it should turn in the same direction as the B field right so wouldnt it point in the same direction as the B field im confused?