- #1
cdummie
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Homework Statement
Through linear conductor flows current I, with direction shown in the picture. Axis where conductor is placed is common edge of three areas with different ferromagnetic materials. They form angles θ1, θ2, θ3 (θ1 + θ2 + θ3 = 2π). If space is filled with homogeneous materials with permeabilities μ1, μ2, μ3 respectively, find intensity of magnetic field vector for arbitrary point in the space due to linear conductor.
Homework Equations
Generalized Ampere's law.
The Attempt at a Solution
This is my attempt:
Considering the direction of the current, it's obvious that intensity of magnetic field vector depends on the distance from the linear conductor. Since the vector B is normal to the boundary of two materials, from the boundary conditions we have that B is same for any point with same distance from the conductor regardless of the material, which means that H is different in different materials.
Using generalized Ampere's law we have:
∫H*dl=∫H*dl*cos(H,dl)= H1*θ1*r + H2*θ2*r + H3*θ3*r
∑I=IIf we express H2 and H3 as B/μ2 and B/μ3 respectively we get the expression for H1 and we can do similar thing for H2 and H3.
so,
H1=(I-B*r(θ2/μ2 + θ3/μ3))/θ1*r
Is this correct, and is this reasonable approach?