Calculate Magnetic field using Ampère's law

AI Thread Summary
The discussion revolves around calculating the magnetic field using Ampère's law, particularly in the context of a toroid. The key equation derived is H = (N*I) / 2πr, leading to B = μ(N*I) / 2πr, where N is the number of turns, I is the current, and r is the radius. The importance of symmetry in applying Ampère's law is emphasized, as it simplifies calculations for mean H-fields in various configurations like transformers and solenoids. Additionally, there is a query about visualizing the magnetic field in Octave using the quiver function, suggesting the need to vary parameters like radius and current intensity to observe different conditions. The discussion highlights the practical application of theoretical concepts in computational tools.
Miss_Fire
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Homework Statement


I have an assignement in school. The statement is: chose a distribution of electric curents for which you can calculate easily the magnetic field (for example, using Ampère's law). Describe your distribution and explain the way you calculate the magnetic field.

Homework Equations


integrals.png

The Attempt at a Solution


I think that I have to find H. For example, if i chose k=1 (one electric current), and a value for I_1 then i'll have to calculate H from the first integral, but I don't know how. This is just my opinion, I'm not even sure if those are the right equations to solve this because the statement seems a little bit vague to me and I'm unfamiliar with this topic.[/B]
 
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Miss_Fire said:
i'll have to calculate H from the first integral, but I don't know how.
An example: Say you have some toroid:
images?q=tbn:ANd9GcTxqYwI2T0HTZMq9jY0RBHgnehbJc_ooT4gPZkpQjg45fROqR1U.jpg

Amperes law states that if you choose some (closed) circulation path ( blue dotted circle ), the mean value of H can be calculated from:

circulation H⋅ds = N*I ( s is length of the path, N is the number of turns ( 18 ) ). N*I is the amount of current that passes through an area, surrounded by the circulation path. This includes separated currents passing in separated coils/wires. So if you choose r > b ( or r < a ), H will be zero, because the summed amount of current through that surrounded area will be zero.

Here H is constant (symmetrical reasons), so it could be written: H*∫ ds = N*I → H * 2πr = N*I → H = (N*I) / 2πr

B = μH → B = μ(N*I) / 2πr

Amperes law is also used to calculate mean H-fields within transformers, solenoids, etc. If a H-field in an exact location is to be calculated, Biot-Savart must be used. But Amperes law is very efficient, calculating cases with some symmetry included.
 
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Hesch said:
An example: Say you have some toroid:
images?q=tbn:ANd9GcTxqYwI2T0HTZMq9jY0RBHgnehbJc_ooT4gPZkpQjg45fROqR1U.jpg

Amperes law states that if you choose some (closed) circulation path ( blue dotted circle ), the mean value of H can be calculated from:

circulation H⋅ds = N*I ( s is length of the path, N is the number of turns ( 18 ) ). N*I is the amount of current that passes through an area, surrounded by the circulation path. This includes separated currents passing in separated coils/wires. So if you choose r > b ( or r < a ), H will be zero, because the summed amount of current through that surrounded area will be zero.

Here H is constant (symmetrical reasons), so it could be written: H*∫ ds = N*I → H * 2πr = N*I → H = (N*I) / 2πr

B = μH → B = μ(N*I) / 2πr

Amperes law is also used to calculate mean H-fields within transformers, solenoids, etc. If a H-field in an exact location is to be calculated, Biot-Savart must be used. But Amperes law is very efficient, calculating cases with some symmetry included.

Thank you for your explanation! I have one more question: I need to represent this magnetic field in Octave. We generally use the quiver function: quiver(X,Y,U,V) draws vectors at each pair of elements in X and Y. If X and Y are vectors, length(X)=n and length(Y)=m, where [m,n]=size(U)=size(V). The vector X corresponds to the columns of U and V, and vector Y corresponds to the rows of U and V. According to your formula (B = μ(N*I) / 2πr), I need somehow to vary the value of some parameters in RHS of the equation, so I can calculate the value of B in different conditions (I suppose that the radius or intensity or both of them should be varied).
 
Miss_Fire said:
Thank you for your explanation! I have one more question: I need to represent this magnetic field in Octave. We generally use the quiver function: quiver(X,Y,U,V) draws vectors at each pair of elements in X and Y. If X and Y are vectors, length(X)=n and length(Y)=m, where [m,n]=size(U)=size(V). The vector X corresponds to the columns of U and V, and vector Y corresponds to the rows of U and V. According to your formula (B = μ(N*I) / 2πr), I need somehow to vary the value of some parameters in RHS of the equation, so I can calculate the value of B in different conditions (I suppose that the radius or intensity or both of them should be varied).

PS: we use the linspace function to get equidistant points in an interval or the meshgrid function.
 
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