Calculate Magnitude of Torque for Flywheel

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To calculate the torque required for a flywheel with a diameter of 1.10 m and mass of 510 kg to reach an angular velocity of 4.00 x 10^3 rev/min in 2.85 minutes, the moment of inertia (I) is first determined using the formula I = mR², resulting in 154.275 kgm². The torque (τ) is then calculated using τ = Iα, where α is the angular acceleration derived from previous calculations. The computed torque value is 377.819 Nm, but this answer was noted as incorrect. The discussion highlights the importance of accurate calculations and the proper representation of symbols in equations. Clarification on the angular acceleration value is also emphasized for correct torque computation.
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Homework Statement



Massive spinning flywheels (disks) can be used for storing energy. Consider a flywheel with a diameter of 1.10 m and a mass of 510 kg. A constant force of magnitude F is applied tangentially to the rim of the flywheel to accelerate it from rest to 4.00 x 103 rev/min during 2.85 min.

(b) What magnitude of torque is necessary to cause this angular acceleration?

Homework Equations



I = mR^{2}
\tau = I\alpha

The Attempt at a Solution



I = mR^{2}
I = (510kg)\ast(.55m)^{2}
I = 154.275 kgm^{2}

\tau = I\alpha
\tau = (154.275kgm^{2})\ast(2.449rad/s^{2}
\tau = 377.819 Nm

The answer was incorrect. Also the angular acceleration was derived from part a and is the correct number. Thanks for the help.
 
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the Tau and Alpha symbols are not suppose to be superscripts. i screwed up the tex
 
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