Calculate Mass of Planet with Density 4950 kg/m3 and Velocity 3.55 km/s

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The discussion centers on calculating the mass of a newly discovered planet with a density of 4950 kg/m3 and a satellite orbiting at a velocity of 3.55 km/s. An initial formula was proposed, but the calculated mass of 3.3*10^47 kg was found to be incorrect. Participants pointed out that the formula needed adjustment, particularly in how the terms were structured under the square root. The user acknowledged an oversight in their calculations and expressed a willingness to use LaTeX for clarity in future discussions. Accurate mass calculation requires careful attention to the formula's structure and proper notation.
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1. A newly found planet with a density of 4950 kg/m3 has no atmosphere and is orbited by a low altitude satellite with an orbital speed of 3.55 km/s. What is the mass of the planet?



2. density*velocity=mass
G= 6.67E-11




3. After a process of equations, I ended up with mass= sqrt(V^6)/(G^3*density*4/3*pi). Subbing in the values and converting 3.55 km/s to 3550 m/s, I get sqrt(3550^6)/(6.67E-11)^3(4950)(4/3*3.14) to get an answer of 3.3*10^47 kg

This isn't the right answer, and I'm not sure where I screwed up. Much appreciated..
 
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clockworks204 said:
3. After a process of equations, I ended up with mass= sqrt(V^6)/(G^3*density*4/3*pi). Subbing in the values and converting 3.55 km/s to 3550 m/s, I get sqrt(3550^6)/(6.67E-11)^3(4950)(4/3*3.14) to get an answer of 3.3*10^47 kg

This isn't the right answer, and I'm not sure where I screwed up. Much appreciated..

You might try to process the equation again. If you show your work we can help more.

As you have written your formula, the only thing under the √ sign is the v6 term. According to my calculations, there should be more than that. Although it might just be your typing notation. Perhaps \LaTeX would be of good use here.

For your convenience I have written your calculated formula in LaTeX (from what I think you meant, anyway -- it's difficult to tell with just text):

m = \frac{\sqrt{v^6}}{\frac{4}{3}G^3 \pi \rho}

You might wish to modify that formula.

[Edit: If you don't know \LaTeX, but whould like to use my equation as an example, click on it and it should open up the LaTeX code which you can copy, and modify in your own post. Or, we can just stick with normal text if \LaTeX doesn't suit you. Alternately, you can click on the "\Sigma" symbol in the upper right hand corner of the editing toolbox (make sure you "Go Advanded" if you don't see it), and there is a menu there that you can use to generate LaTeX code from items on the menu.]
 
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Yep you caught my error. I simply missed taking the square root of the solution because there was quite a bit going on. I'll try using Latex next time...I was unaware of it. Thank for you help collinsmark.
 
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