Calculate Matt's Landing Speed on a Skateboard | Mass & Velocity Included"

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Matt is gliding on his skateboard at 4.00 m/s before jumping backward, propelling the skateboard forward at 8.00 m/s. The initial momentum is calculated as the combined mass of Matt and the skateboard multiplied by their initial speed. The final momentum equation considers Matt's speed as he lands and the skateboard's speed after the jump. After solving the equations, the final speed of Matt as he hits the ground is determined to be 3.44 m/s. The calculations highlight the conservation of momentum principle in this scenario.
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Matt is gliding on his skateboard at 4.00 m/s. He suddenly jumps backward off the skateboard, kicking the skateboard forward at 8.00 m/s. Matt's mass is 50 kg and the skateboard's mass is 7 kg. How fast is Matt going as his feet hit the ground?

This what I did:
P_f = P_i

v_f(50kg + 7kg) = 50kg*4m/s + 7kg*4m/s
v_f = 4.49m/s ?
 
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Hmmm, not sure what you did.
The initial momentum you calculated looks correct: (50+7)*4. But the total final momentum is Vf*50+7*8, where vf is the speed of Matt. Solving for Vf, I get 3.44 m/s. I'm probably wrong though.
 
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