Calculate Maximum Velocity with Swing Chain Length and Angle

Click For Summary
SUMMARY

The discussion focuses on calculating the maximum velocity of a swing using a chain length of 1.8 meters and an initial angle of 30 degrees from the vertical. The total mass of the swing and the person is 72 kg. The key equations utilized include the conservation of mechanical energy, specifically Ui + Ki = Uf + Kf, and the kinetic energy formula K = 1/2 mv². The final calculation yields a maximum velocity of 1.53 m/s at the bottom of the swing, confirming that only translational kinetic energy is necessary for this scenario, as rotational kinetic energy does not apply due to the point mass assumption.

PREREQUISITES
  • Understanding of conservation of mechanical energy principles
  • Familiarity with kinetic energy equations
  • Basic knowledge of trigonometry for height calculations
  • Concept of rotational motion and its relation to kinetic energy
NEXT STEPS
  • Study the principles of conservation of energy in mechanical systems
  • Learn about the differences between translational and rotational kinetic energy
  • Explore the effects of varying angles on swing dynamics
  • Investigate experimental methods for measuring swing velocity
USEFUL FOR

Students in physics, educators teaching mechanics, and anyone interested in understanding the dynamics of pendulum motion and energy conservation principles.

drobtj2
Messages
5
Reaction score
0

Homework Statement



Using the length of a swing's chain (1.8m) and using the angle the swing starts at relative to the vertical (30 deg.) devise a method to calculate the max veloc. of the swing at the bottom. Assume mass of person+swing=72 kg

Homework Equations



Ui+Ki=Uf+Kf
K=1/2 mv^2
U=mgh
h= 1.8 cos 30
Krot= 1/2 Iw^2


The Attempt at a Solution



(m)(9.8)(.24)=1/2 m v^2 +1/2 Iw^2
2.35= 1/2 v^2+ 1/2 r^2 (v^2/r^2)
2.35= 1/2 v^2 + 1/2 v^2
2.35=v^2
v=1.53 m/s

Do I use the rotational kinetic energy when solving the problem? It seems like I should because of the rotational motion but I'm not sure.
 
Physics news on Phys.org
you can use rotational energy, altough it's not really necessary since all the mass is in one point and all the forces act on this point.
you can't use BOTH howvever. The rotational energy of the swinger is the same energy as the ordinary kinetic energy.
 
Thanks, this problem was part of a lab, and later the experimental and theoretical data didnt match, so i figured my method had been wrong, and I got good results using only kinetic.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 26 ·
Replies
26
Views
3K
  • · Replies 11 ·
Replies
11
Views
5K
Replies
8
Views
3K
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
4K