Calculate Moles of Acetylene & O2 in C2H2+O2 Reaction at 60C, 10mmHg

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The discussion focuses on calculating the moles of acetylene (C2H2) and oxygen (O2) in a combustion reaction at specific conditions. The balanced reaction is C2H2 + 5/2 O2 -> 2CO2 + H2O, with the final gaseous mixture containing O2, CO2, and H2O. Participants suggest using Raoult's law to find the mole fraction of water and applying the ideal gas law (PV=nRT) to determine the moles of water, which can then be used to calculate the original moles of C2H2 and O2. The total number of moles must be established first, followed by the moles of water to derive the amounts of the reactants. The conversation emphasizes the step-by-step approach to solving the problem.
matthewsyq1995
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Acetylene (C2H2) is reacted with excess O2 in a container. After complete reaction, the volume of the gaseous mixture of the combustion products is 300ft3 at 60C and 10mmHg gauge pressure. P(atm) is 735mmHg. The relative humidity if the product gas is 100% with no condensed water present. Calculate the moles of acetylene and oxygen in the original mixture.

GIven: Saturated vapour pressure of water at 60C is 150mmHg
Pls help!

I don't really know how to continue
 
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What is the balanced chemical reaction equation for the reaction of acetylene with oxygen? How many moles of gases are present in the final state of the system? What are the gases present in the final state of the system? How many moles of water are present in the final state of the system?
 
The equation is C2H2 + 5/2 O2 -> 2CO2 + H2O
Gases in final state would be O2, CO2, and H2O.
I can find the mole fraction of H20 through Raoults law but i don't really know how to continue from there
 
matthewsyq1995 said:
The equation is C2H2 + 5/2 O2 -> 2CO2 + H2O
Gases in final state would be O2, CO2, and H2O.
I can find the mole fraction of H20 through Raoults law but i don't really know how to continue from there
OK. How many moles of water are there? How many moles of C2H2 reacted to produce this amount of water?
 
Chestermiller said:
OK. How many moles of water are there? How many moles of C2H2 reacted to produce this amount of water?
Hmmm ok correct me if I am wrong.
Mole fraction (h2o) = 150/745 = 0.20134
use this to find the moles of h2o using PV= nRT, assuming ideal gas.

use n to find moles of c2h2 and o2 in original mixture.
 
matthewsyq1995 said:
Hmmm ok correct me if I am wrong.
Mole fraction (h2o) = 150/745 = 0.20134
use this to find the moles of h2o using PV= nRT, assuming ideal gas.

use n to find moles of c2h2 and o2 in original mixture.
Correct.

First find total number of moles. Then get moles of h20. From this get original moles of c2h2. From this get moles of co2. From this info, get original moles of o2.
 
Chestermiller said:
Correct.

First find total number of moles. Then get moles of h20. From this get original moles of c2h2. From this get moles of co2. From this info, get original moles of o2.

Alright! thnks!
 
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