Calculate Moment of Inertia: Axis of Object in Figure | L, M, m1, m2

AI Thread Summary
The discussion focuses on calculating the moment of inertia for an object based on its constituents, specifically in terms of L, M, m1, and m2. Users are encouraged to express their calculations for the individual moments of inertia, including contributions from the rod and masses m1 and m2. Initial attempts at the calculation include formulas that combine the mass contributions and dimensions. The importance of summing the individual moments of inertia to find the total is emphasized. Accurate calculations are essential for determining the overall moment of inertia about the specified axis.
dtesselstrom
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Determine the moment of inertia about the axis of the object shown in the figure. Enter your answer in terms of L, M, m1, and m2.
 

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What have you tried so far?

By the way, this belongs in the homework section.
 
ok sorry for posting in wrong section.
Ive tried 1/12(m1+m2+M)*L^2 and 1/12(m1+m2+M)*L^2+1/4*m1*L^2-1/16*m2*L^2
 
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The moment of inertia of an object about an axis is just the sum of the moments of inertia of its constituents about that axis; i.e. in this case:
I=I_{rod}+I_{m1}+I_{m_2}

What do you get for these separate moments of inertia?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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