Calculate Normal Force: 55 N Box on Table with 35 N Box and 28 N Hanging Box

AI Thread Summary
To calculate the normal force exerted by the table on the 55 N box, consider the weights of all boxes involved. The 55 N box supports the 35 N box, while the 28 N hanging box affects the tension in the rope connected to the 35 N box. The normal force on the 55 N box is equal to its weight plus the weight of the 35 N box, minus the tension created by the hanging 28 N box. The tension in the rope due to the hanging box reduces the effective weight on the table. Therefore, the normal force is influenced by the combined weights and the tension from the hanging box.
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You have a box that wieghs 55 N sitting on a table. On top of that box there is another box that weighs 35 N attached to a frictionless rope that is around a frictionless pully. At the other end of the rope there is another box that is hanging with a weight of 28 N. What is the normal force that the table exerts on the 55 N box?
 
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Think 3rd law. It might help to draw this out.
 
what?

So what does that mean ? what is the force of the box that is hanging have to do with this and does that take additional force off of the 35 N box ?
 
How much force is exerted on the table? You've got the 55N box and the 35N box, but the 35N box is offset by the 28N box.
 
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