Calculate Resistive Force of Water on Speedboat | 130 hp Required for 15 m/s

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To calculate the resistive force of water on a speedboat moving at 15 m/s with a power requirement of 130 hp, the equation P=F(V) is used. The initial attempt yielded an incorrect force due to unit conversion errors, as horsepower is not an SI unit. The correct approach involves converting horsepower to kilowatts and ensuring all units are consistent. After addressing the unit issue, the resistive force was determined to be approximately 6.47x10^3 N or 1450 lbs. Proper unit conversion is essential for accurate calculations in physics problems.
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Homework Statement


A speedboat requires 130 hp move at a constant speed of 15 m/s. Calculate the resistive force due to the water at that speed.


Homework Equations


P=F(V)


The Attempt at a Solution


I attempted to use Newtons first law that says in order for a object to be at rest the sum of the forces must be zero. Therefore I thought that the horsepower for the force of friction must be the same as the propulsion. So
130=F(15)
F= 8.6
The answer is 6.47x10^3 N or 1450 lbs
 
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BrainMan said:

Homework Statement


A speedboat requires 130 hp move at a constant speed of 15 m/s. Calculate the resistive force due to the water at that speed.


Homework Equations


P=F(V)


The Attempt at a Solution


I attempted to use Newtons first law that says in order for a object to be at rest the sum of the forces must be zero. Therefore I thought that the horsepower for the force of friction must be the same as the propulsion. So
130=F(15)
F= 8.6
The answer is 6.47x10^3 N or 1450 lbs
The problem is with the units.

Horsepower is not an SI unit.
 
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F = 8.6 what? What are the units? You forgot to convert the units to some consistent system. hp is a British unit while m/s is International.
 
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BrainMan said:

Homework Statement


A speedboat requires 130 hp move at a constant speed of 15 m/s. Calculate the resistive force due to the water at that speed.


Homework Equations


P=F(V)


The Attempt at a Solution


I attempted to use Newtons first law that says in order for a object to be at rest the sum of the forces must be zero. Therefore I thought that the horsepower for the force of friction must be the same as the propulsion. So
130=F(15)
F= 8.6
The answer is 6.47x10^3 N or 1450 lbs

There's a standard conversion from hp to kW that every petrolhead will be familiar with. Use that conversion (google it) and work purely in SI units.
 
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OK I see what I did and found out how to solve the problem. Thanks everyone!
 
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