I Calculate Skydiver Deceleration Force

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To calculate the force exerted on a skydiver decelerating from 120 mph to 30 mph in one second, the deceleration is determined to be 132 ft/sec², equivalent to about 4 g's. This calculation assumes contact deceleration, which equipment manufacturers aim to optimize for safety. The discussion highlights the importance of managing not just the deceleration but also the jerk to minimize the initial impact force. The goal is to create a smoother deceleration experience for the skydiver. Understanding these dynamics is crucial for both safety and comfort during skydiving.
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I'm wondering how to calculate the force exerted on a skydiver as they decelerate from their terminal velocity of approximately 120 mph to approximately 30 mph in the course of one second, as I have seen and felt while skydiving. Thank you all in advance.
 
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120 mph is 176 ft/sec and 30 mph is 44 ft/sec. So the deceleration is 132 ft/sec^2. This is about 4 g's.
 
Note that that assumes contact deceleration, which I would think equipment manufacturers try to achieve.
 
Instead of constant deceleration, there's some effort to also reduce the jerk, so that the initial deceleration is not as great as the maximum deceleration.
 
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