Calculate the actual depth of the trout

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SUMMARY

The discussion centers on calculating the actual depth of a trout observed from a fishing boat, with specific parameters provided by the user, Sam. The apparent depth is estimated at 2.0 meters, with Sam's eyes positioned 1.0 meter above the water's surface and an observation angle of 45 degrees. Utilizing Snell's Law, the refractive indices for water (1.33) and air (1.00) are applied to determine the actual depth of the trout, which requires further geometric analysis and diagrammatic representation of light paths. The community emphasizes the importance of visual aids in understanding the refraction of light at the water's surface.

PREREQUISITES
  • Understanding of Snell's Law and refractive indices
  • Basic geometry for calculating angles and depths
  • Ability to interpret and create diagrams of light paths
  • Familiarity with the concept of refraction in different media
NEXT STEPS
  • Study Snell's Law in detail to understand light refraction
  • Learn how to draw ray diagrams for light behavior at interfaces
  • Explore geometric methods for calculating depths in optics
  • Investigate the effects of different angles of incidence on light refraction
USEFUL FOR

This discussion is beneficial for physics students, educators in optics, and anyone interested in the practical applications of light refraction in real-world scenarios, such as fishing or underwater observation.

Shaley
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Sam is sitting in her fishing boat watching a trout swim below the surface. She guesses the apparent depth of the trout at 2.0m. She estimates that her eyes are about 1.0 m above the water's surface, and that the angle at which she's observing the trout is 45 degrees.

a) draw a diagram to show the ACTUAL depth of the trout and the path of light from the trout to Sam's eyes
b) Calculate the actual depth of the trout

MY WORK SO FAR:
ni=1.33 for water (the "i" stands or incident)
nR=1.00 for air (to 3 significant digits) (the "r" stands for refracted)

sinangle1=[(nR)(sinangleR)] divided by ni
=(1.00)(.707) divided by 1.33
=0.534
anglei=32.3degrees

I don't know where to go from here...please help.
 
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Can you do what the question asks and draw a diagram of the light rays striking the fishermans eyes? What happens at the surface?

Is it bent towards or away from the fisherman? If you know that, it becomes a problem in geometry.
 
sorry, I still don't understand.please explain more.
 
denverdoc said:
Can you do what the question asks and draw a diagram of the light rays striking the fishermans eyes? What happens at the surface?

Is it bent towards or away from the fisherman? If you know that, it becomes a problem in geometry.

I would guess that the rays of light striking the fisherman's eyes are bent toward the fisherman's eyes.
 
Hee, hee poorly worded.

Words are way too often a lousy substitute for math and a diagram. So correct that which should read whether the rays reflected from the fish were directed above or below his eyes before hitting the surface.
 

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