Calculate the mangitude and direction of the force

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Homework Help Overview

The discussion revolves around calculating the magnitude and direction of a force required to walk from home to school, given that this force acts at a 70-degree angle to the horizontal and is equal to the person's weight. The mass of the individual is provided as 120 lb or 48 kg.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of weight using the formula w=mg and explore the components of the force acting in the horizontal direction. There are attempts to verify the calculations of the horizontal force component using trigonometric functions.

Discussion Status

Some participants have provided calculations for the horizontal force component and are seeking confirmation on the accuracy of their results. There is an ongoing exploration of significant figures in the calculations, indicating a productive engagement with the problem.

Contextual Notes

Participants express uncertainty about the correctness of their calculations and seek clarification on significant figures, suggesting a focus on precision in their answers.

raman911
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Homework Statement



Assume that force the force required to walk from home to school is on a 70 degree angle to the horizontal surface. This force is equal to your weight.
mass is 120lb or 48 kg
a) calculate weight.

b) calculate the mangitude and direction of the force that causes you to move in the horizontal direction.



The Attempt at a Solution



a)
w=mg
w=48kg*9.8N/kg
w=470.4N
b)
please helpppppppppppp
 
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F_x = mg*cos(70)
 
=48kg*9.8N/kg*cos (70)
=160.88
is that right
 
help me....
 
raman911 said:
=48kg*9.8N/kg*cos (70)
=160.88
is that right

Looks good; just check your significant figures.
 

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