The problem statement, all variables and given/known data A rock of mass 1.10kg and volume 283cm3 is irregular shape. A person throws the rock with a launch angle of 39.0° (above the horizontal) over flat level ground from a height of 0.668m above the ground. Ground level is at an elevation of 138m above sea level. The rock goes 7.40 m down range before it hits the ground. The rock bounces off the ground achieving a maximum height of 12.0cm and traveling an additional 18.0cm down range before coming to rest with a thud. Find the momentum of the rock at the instant it leaves the thrower’s hand. The attempt at a solution So what I did was V = √2gx (where x is distance) and I got a velocity of 22.54 m/s. I plugged that into the equation P=m*v to get momentum of 24.8 kgm/s However, i'm not sure I did this right at all.