Calculate the original speed of the cue ball

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The discussion focuses on calculating the original speed of a cue ball after it strikes a stationary billiard ball, using the principles of conservation of momentum. Participants emphasize the importance of treating momentum as a vector, requiring the analysis of components both parallel and perpendicular to the cue ball's original path. They clarify that the angle of deflection affects the momentum equations, leading to two separate equations for the components. The conversation highlights that the total momentum in the north-south direction must cancel out, while the east components must equal the initial momentum of the cue ball. Ultimately, the calculations will yield the original speed of the cue ball.
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A 0.40-kg cue ball makes a glancing blow to a stationary 0.30-kg billiard ball so that the cue ball deflects with a speed of 1.2 m/s at an angle of 30.0º from its original path. Calculate the original speed of the cue ball if the billiard ball ends up traveling at 1.5 m/s.

from its original path. Calculate the original speed of the cue ball if the billiard ball ends up traveling at 1.5 m/s.




I think i just use conservation of momentum here pt initial = pt Final? But the 30.0º from it's original path is throwing me off does it even come into it?
 
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panders3 said:
I think i just use conservation of momentum here pt initial = pt Final?
Good.
But the 30.0º from it's original path is throwing me off does it even come into it?
Remember that momentum is a vector. Consider components parallel and perpendicular to the original direction of the cue ball. (You'll end up with 2 equations, one for each component.)
 
Because my original vector is in only one dimension let's say east then the north of one vector has to equal the south of the other vector. Correct?

Plug in the numbers and solve?
 
panders3 said:
Because my original vector is in only one dimension let's say east then the north of one vector has to equal the south of the other vector. Correct?
Yes. Since the initial total momentum is zero in the north-south direction, those components of the final momenta must cancel.

Plug in the numbers and solve?
The above will give you one equation. You'll need another for the east components of the final momenta.
 
and they need to equal the total of the initial vector.
 
panders3 said:
and they need to equal the total of the initial vector.
Sure. Total momentum is conserved.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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