Calculate the resulting charge on each capacitor

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    Capacitor Charge
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Capacitors C1 (6.35 µF) and C2 (2.00 µF) are initially charged in parallel across a 250 V battery, resulting in charges of 1587.5 µC for C1 and 500 µC for C2. After disconnecting them from the battery and each other, they are reconnected in series with opposite plates connected. In this configuration, the charge on both capacitors will equalize to the same value. The final charge on each capacitor can be calculated using the formula for capacitors in series, considering their capacitance values and the total voltage across them. The resulting charges need to be computed based on these principles.
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Capacitors C1 = 6.35 µF and C2 = 2.00 µF are charged as a parallel combination across a 250 V battery. The capacitors are disconnected from the battery and from each other. They are then connected positive plate to negative plate and negative plate to positive plate. Calculate the resulting charge on each capacitor.
q'1 = µC
q'2 = µC

Can someone please help me with this, I don't know what to do.
 
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First you have to find the charge on each capacitor after it has been charged. Then note from the statement of the problem whether the new connection yields a series or parallel connection.

From here, note that if the caps are in series, the resulting charge (if you let the circuit stabilise) on each capacitor will be the same. If they are in parallel, then their final potential differences will be the same. From these 2 conditions you can calculate the final charge on each cap.
 
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