Calculate the velocity of the particle at t=4.0 s.

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To calculate the velocity of a 2.0 kg particle at t=4.0 s, the net force applied is given by F = 3t^2 - 12t. The acceleration can be determined using the formula a = F/m, leading to a = (3t^2 - 12t) / 2. The confusion arises regarding the mass value in the acceleration formula; it should be 2 kg, not 4. By integrating the acceleration over the time interval and adding it to the initial velocity of -6.0 m/s, the final velocity at t=4.0 s can be calculated.
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A 2.0 kg particle is moving along the x-axis to the left with a velocity of v= -6.0 m/s. Suddenly, between times t =0 and t = 4.0 x a net force = 3t^2 – 12t is applied to the particle, where F is in N and t is in s. Calculate the velocity of the particle at t=4.0 s.
I am having trouble making the numbers work. Thanks
 
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Well, what have you tried so far?
 


Someone told me to use this formula but I don't understand why the 4 is in the first equation because the mass is 2 kg
 


Sorry, the formula is
a= force/mass= (3t^2-12t)/4

Why is there a 4?
 

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