Calculate the velocity of the projectile

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Homework Help Overview

The problem involves calculating the velocity of a projectile at a specific height, given an initial velocity and gravitational acceleration. The context is kinematics, specifically projectile motion.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formulation of equations related to projectile motion, particularly focusing on the vertical component of velocity and its dimensional correctness. There is an exploration of the relationship between initial velocity, height, and gravitational effects.

Discussion Status

Some participants have identified potential errors in the original equations presented, particularly regarding the dimensional accuracy of the vertical velocity equation. There is a suggestion for a revised formulation that appears to align better with dimensional analysis.

Contextual Notes

Participants are working under the constraints of neglecting air resistance and using specific values for gravitational acceleration. The original poster's setup and assumptions are being scrutinized for accuracy.

Fadi A.Saif
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Homework Statement


A stone was thrown with initial velocity of 100 m/s. Calculate the velocity of the projectile at 10 m of height. (Consider g=10m/s^2, and neglect the effect of air molecules)


Homework Equations



where's the error in the following sollution?


The Attempt at a Solution


Vr= sqrt((Vx)^2+(Vy)^2)...(1) (Resultant velocity).
Vx= Vi cos(a)...(2)
Vy=Vi sin(a)+(-2gy)...(3)
sub. (2)& (3) in (1)
Vr = sqrt(Vi^2 (cos(a))^2+Vi^2 (sin(a))^2+(-2gy)); taking Vi as a common factor, and sqrt of both sides; we get
Vr = sqrt(Vi^2-2gy) then we proceed by applying the given data from the problem
 
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The error is right here

Vy=Vi sin(a)+(-2gy)

This equation is not dimensionally correct.
 


Thanks Kuruman... so I believe it should be like this
Vy^2= Vi^2 (sin(a))^2 - 2gy.
 


That's more like it.
 

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