Calculate thermistor coefficents

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The discussion focuses on calculating the thermistor coefficients R0 and B for an NTC thermistor using Visual Basic. The equation R = R0.e^(B/T) is transformed by taking the natural logarithm of both sides, leading to ln(R) = ln(R0) + B(1/T), which resembles the linear equation y = c + mx. Participants clarify that R represents the resistance at temperature T in Kelvin, while R0 is the resistance at an arbitrary reference temperature, such as room temperature. A graph of ln(R) versus 1/T is proposed, where the slope corresponds to B and the intercept on the R-axis gives R0. The conversation concludes with confirmation of these relationships and appreciation for the guidance provided.
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I'm using Visual Basic to graph data from a NTC thermistor and temperature sensor (via a DAC card). I want to calculate the thermistor coefficients R0 and B according to the equation (R0 should have subscript 0):
R = R0.e^B/T
T=absolute temperature
R=resistance

I have calculated ln(R) and 1/T but am unsure of how to calculate the coefficients. Any help would be greatly appreciated.
 
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1st step is to take ln of both sides of the equation.
 
Hi grzz, how can I take the ln of both sides if B is unknown?
 
R = R_{o}e^{\frac{B}{T}}

then

lnR = lnR_{o} + B (\frac{1}{T})

Compare with

y = c + mx

which is a straight line graph.
 
Ok I think I'm getting there. So Ro is resistance at an arbitrary temperature eg. room temperature? So what is the first R?
 
R is the value of the resistance at temperature T (in Kelvin).

So one plots a graph of lnR on the vertical axis against 1/T on the horizontal axis and then the intercept on the R-axis will be ... and the slope of the graph will be ...
 
Ok good stuff. I know that the slope is equal to B. Is R0 then equal to the intercept?
 
Ro = intercept on the R-axis.
 
Thanks a million grzz!
 
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