Calculate Total Charge in Cube w/ Electric Field E = 2.0i − 3.0j

  • Thread starter Thread starter vande060
  • Start date Start date
  • Tags Tags
    Flux
AI Thread Summary
The discussion focuses on calculating the total charge within a cube in an electric field defined as E = 2.0i − 3.0j. The user intends to apply Gauss's law, using the formula ∫ E da = q/εo, to find the charge. They plan to evaluate the electric field on the cube's surfaces, particularly those aligned with the i and j directions. Clarification was sought regarding the problem's wording, which was confirmed to be accurately represented. The user is on the right track and aims to solve for the charge q using the electric field and surface area calculations.
vande060
Messages
180
Reaction score
0

Homework Statement


A region of space around the origin contains an electric field E = 2.0i − 3.0 j. Such a field cannot exist
in empty space. Find the total charge within a cube of side a = 0.5m centered on the origin, with its six faces
possessing normals in the six cardinal directions ±i,±j,±k.

Homework Equations



∫ E da = q/εo

The Attempt at a Solution



So I know what E is so I can plug that into gauss' law and dot that into the surface area of a side of the cube, then set that equal q/εo

I really only have to be concerned he with +/- i and +/- j
(2.0i − 3.0 j) . (+/-a2i +/-a2j) = q/εo

Is this right so far, if it is ill just solve for q, but I am not sure if I am right to this point
 
Physics news on Phys.org
You will have to explain the problem better. Can you give us the actual wording of the problem?

AM
 
Andrew Mason said:
You will have to explain the problem better. Can you give us the actual wording of the problem?

AM

Thanks for your response. I copied and pasted the problem word for word in my book under headline 1, I don't know how to make it clearer, that's verbatim. What i got from it was to use the electric field given, and plug that into the formula for flux(under headline 2) and solve for q.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top