Calculate velocity when time is equal

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To calculate the velocity required for a ball to hit an object 12m away and 8m above its initial height, one must consider projectile motion principles. The horizontal and vertical components of velocity can be determined using the equations Vx = 12m/t and Vy = 8m/t. The angle of projection can be found using the tangent function, resulting in an angle of approximately 33.69 degrees. However, without additional information such as time or total velocity, determining the exact velocity remains challenging. Understanding the kinematic equations and projectile motion is essential for solving this problem effectively.
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1. Ball is thrown at an object that is 12m away and 8m above the initial height of the ball. At what velocity must the ball be thrown to hit the object?
2. V=d/t
3. You can find the angle at which the ball must be thrown by using tan^-1= (8/12)= 33.69 degrees, not sure if that helps much. Vx=12m/t, vy=8m/t, so at what velocity will the time be equal? Do i have enough info...?
 
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Vx=12mxt, vy=8mxt,

v = d/t. How did you write the above equations? The angle also not correct.

It is a projectile motion.

You have to consider the components of velocity along the horizontal and vertical direction. Then use the kinematic equations for horizontal and vertical displacement.
 
yes, ok so for the horizontal velocity its velocity horizontal=displacement horizontal / time. then for velocity vertical = displacement vertical / time, what do i do next?
 
First of all go through the projectile motion from any site or textbook. Learn the basic things. Then I will help you.
 
Ok, i know the basics but i just do not know what to do with so few givens. How can i find the velocity without time and vice versa?
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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