- #1
Idividebyzero
- 64
- 0
1. A particle moving in the xy plane undergoesa displacement ~s = (sxˆı + sy ˆ|), with sx =
1.57 m, sy = 3.21 m, while a constant force F=(Fxˆı+Fyˆ|),withFx=5.81N,Fy=3.93 N, acts on the particle.
Calculate the the work done by vector F.
.
2.W=FDcos(theta)
inverse tangent
3. first found the magnitude of the resultant vector for the displacement via the theorum of pathagoreas. Using the same method i found the magnitude of the force resultant. Used inverse tangent times y over x for the angle. with those values i pluged into W=F*Dcos(theta). answer was incorrect. Okay, thought about it some more, the only work done through the applied force is on the X axis using just the x vectors calculated the work, that is also incorrect.
1.57 m, sy = 3.21 m, while a constant force F=(Fxˆı+Fyˆ|),withFx=5.81N,Fy=3.93 N, acts on the particle.
Calculate the the work done by vector F.
.
2.W=FDcos(theta)
inverse tangent
3. first found the magnitude of the resultant vector for the displacement via the theorum of pathagoreas. Using the same method i found the magnitude of the force resultant. Used inverse tangent times y over x for the angle. with those values i pluged into W=F*Dcos(theta). answer was incorrect. Okay, thought about it some more, the only work done through the applied force is on the X axis using just the x vectors calculated the work, that is also incorrect.
