Calculate x-intercept for f(x)

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To find the x-intercept of the function f(x) = 0.02605x - 0.01908, the equation is set to zero, resulting in x = 0.732 when calculated to three significant figures. Another participant confirmed their calculation of 0.7324 to four significant figures, suggesting verification by substituting back into the original equation. It was noted that due to rounding, f(0.7324) would not yield exactly zero. The discussion emphasizes the importance of checking calculations for accuracy.
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Homework Statement


f(x) =0.02605x-0.01908

Calculate the x-axis intercept for the function above.


Homework Equations


f(x) =0.02605x-0.01908


The Attempt at a Solution



0 = 0.02605x - 0.01908
0.02605x = 0.01908
x = 0.732 (3 s.f.)
 
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rollcast said:

Homework Statement


f(x) =0.02605x-0.01908

Calculate the x-axis intercept for the function above.


Homework Equations


f(x) =0.02605x-0.01908


The Attempt at a Solution



0 = 0.02605x - 0.01908
0.02605x = 0.01908
x = 0.732 (3 s.f.)

What's your question?
 
looks right, I got 0.7324 to 4 sig figures

Just check it by plugging in it into thee original eqn to verify that f(x) is zero.
 
Mark44 said:
What's your question?

I'm trying to calculate the x - intercept of the line, f(x) =0.02605x-0.01908.
 
rollcast said:
I'm trying to calculate the x - intercept of the line, f(x) =0.02605x-0.01908.
I can see that you did that, but what is your question?
 
Mark44 said:
I can see that you did that, but what is your question?

I wanted to see if my result was correct as I'm not familiar with the f(x) = ... notation.
 
jedishrfu said:
looks right, I got 0.7324 to 4 sig figures

Just check it by plugging in it into thee original eqn to verify that f(x) is zero.

f(0.7324) won't work out to be exactly zero, because of the rounding.
 
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